2y(2y+3y^2)-y^2(3-y)=0

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Solution for 2y(2y+3y^2)-y^2(3-y)=0 equation:


Simplifying
2y(2y + 3y2) + -1y2(3 + -1y) = 0
(2y * 2y + 3y2 * 2y) + -1y2(3 + -1y) = 0
(4y2 + 6y3) + -1y2(3 + -1y) = 0
4y2 + 6y3 + (3 * -1y2 + -1y * -1y2) = 0
4y2 + 6y3 + (-3y2 + 1y3) = 0

Reorder the terms:
4y2 + -3y2 + 6y3 + 1y3 = 0

Combine like terms: 4y2 + -3y2 = 1y2
1y2 + 6y3 + 1y3 = 0

Combine like terms: 6y3 + 1y3 = 7y3
1y2 + 7y3 = 0

Solving
1y2 + 7y3 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), 'y2'.
y2(1 + 7y) = 0

Subproblem 1

Set the factor 'y2' equal to zero and attempt to solve: Simplifying y2 = 0 Solving y2 = 0 Move all terms containing y to the left, all other terms to the right. Simplifying y2 = 0 Take the square root of each side: y = {0}

Subproblem 2

Set the factor '(1 + 7y)' equal to zero and attempt to solve: Simplifying 1 + 7y = 0 Solving 1 + 7y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 7y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 7y = 0 + -1 7y = 0 + -1 Combine like terms: 0 + -1 = -1 7y = -1 Divide each side by '7'. y = -0.1428571429 Simplifying y = -0.1428571429

Solution

y = {0, -0.1428571429}

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